Math, asked by neelam6819, 1 year ago

Compare the two functions n2 and 2n /4 for various values of n. Determine when the second becomes larger than the first.

Answers

Answered by Anonymous
5
hey mate
here's the solution
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Answered by slicergiza
10

Answer:

Let,

f(n) = n^2 and g(n) = \frac{2n}{4}

Since, f(n) is a quadratic function,

So, its domain = set of all real numbers,

Also, the vertex of f(n) = (0,0) where f(n) is an upward parabola,

Thus, range of f(n) = All real numbers greater than 0,

While, g(n) is a line,

Domain = Set of all real numbers,

Range of g(n) = Set of all real numbers,  ( the range of a linear function is always R )

If g(n) > f(n)

\frac{2n}{4} > n^2

\frac{1}{2} > n

That is, for all real values less than 1/2, g(n) is greater than f(n).

If g(n) < f(n),

\frac{2n}{4} &lt; n^2

\frac{1}{2} &lt; n

That is, for all real values greater than 1/2, f(n) is greater than g(n).

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