Question

compare time period of simple pendulum 39.2 cm long at the place where G is 9.8 metre per second square​

Answer 1

Answer:

The Time period should be 12.28 s.

Explanation:

Length = 39.2 cm

g = 9.8 m/s²

∴ Time Period = 2$\pi$ * √l/g

= 2*3.14 * √39.2/9.8

= 6.14 * √4

= 6.14 * 2

= 12.28 s

Hope rhis helps.