Question

comparewater vapours of benzene at 30 degree celsius and and its water vapuors at 300 kelvin
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Answer 1

Explanation:

This is the case of relative lowering of vapour pressure when solute is added to pure solution.

PoΔP=121.8121.8−120.2=121.81.6=0.013

PoΔP=n2+n1n2=Mw215+78.125015/Mw2=Mw2(Mw215+3.2)15

0.013=15+3.2Mw215

0.013×15+3.2×0.013Mw2=15

0.195×0.0146Mw2