Question

Comparison Method 7x +3y-44=0 ;. 3x - 2y-9=0​

Answer 1

Answer:

3x – 2y + 2y = 2 + 2y

or, 3x = 2 + 2y

or, 3x/3 = (2 + 2y)

or, x = (2 + 2y)/3

Therefore, x = (2y + 2)/3

Step-by-step explanation:

I hope it help to you

Answer 2

Answer:

By Comparison method value of x is 5 and value y is 3.

Step-by-step explanation:

Here given two equations are

$7x + 3y - 44 = 0....(1) \\ 3x - 2y - 9 = 0.....(2)$

From equation (1),

$7x + 3y - 44 = 0 \\ 7x = 44 - 3y \\ x = \frac{44 - 3y}{7} ....(3)$

And from equation (2),

$3x - 2y - 9 = 0 \\ 3x = 2y + 9 \\ x = \frac{2y + 9}{3} ......(4)$

We are comparing equation (3) and (4),

$\frac{44 - 3y}{7} = \frac{2y + 9}{3}$

By cross multiplication,

$3(44 - 3y) = 7(2y + 9)$

$132 - 9y = 14y + 63$

$14y + 9y = 132 - 63 \\ 23y =6 9 \\ y = \frac{69}{23} \\ y = 3$

We are putting value of y in equation (3),

$x = \frac{44 - 3 \times 3}{7} \\ x = \frac{44 - 9}{7} \\ x = \frac{35}{7} \\ x = 5$

This is a problem of Algebra.

Some important Algebra formulas,

a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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