Physics, asked by aryanpandit2533, 4 months ago

comparison of emf of two cells using potentiometer with construction and working​

Answers

Answered by tejaskulkarni26
0

Explanation:

Using a potentiometer, we can determine the emf of a cell by obtaining the balancing length l. Here, the fall of potential along the length l of the potentiometer wire is equal to the emf of the cell, as no current is being drawn from the cell. Then, or, ; where k is the potential gradient along the wire.

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Answered by Anonymous
0

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Uses of Potentiometer-

Comparison of emf of two cells using Potentiometer. The measuring instrument called a potentiometer is essentially a voltage divider used for measuring electric potential (voltage); the component is an implementation of the same principle, hence its name.

Connect the positive poles of the cells to the terminal and the negative poles to the terminal a and b of the two way key . Insert the plug in the key K and also in between the terminals a and c of the two way key . Slide the jockey gently over the potentiometer wires until you obtain a point of no deflection

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