Chemistry, asked by thaara6282, 8 months ago

comparison to a 0.02 M solution of glucose, the depression in freezing point of a 0.02 M AlCl3 solution is _____. *
2 points
a) the same
b) about twice
c) about three times
d) about four times
e) none of these​

Answers

Answered by gunduravimudhiraj76
21

Answer:

comparison to a 0.02 M solution of glucose, the depression in freezing point of a 0.02 M AlCl3 solution is _____. *

2 points

a) the same

b) about twice

c) about three times

d) about four times

e) none of these

Answered by Nithyar6
0

Answer:

about four times

Explanation:

Vant hoff factor for glucose is 1

vant hoff factor for AlCl3 is 4.

Vant hoff factor is directly related to the depression in freezing point.Hence,the depression in freezing point of glucose is 4 times than the aluminium chloride.

Vant hoff factor is the ratio of actual concentration of particles produced and concentration calculated from molecular mass.

Freezing point depression is the decrease of freezing point of solvent on addition of non volatile solute

For more references:

https://brainly.in/question/16504651?utm_source=android&utm_medium=share&utm_campaign=question

https://brainly.in/question/15904744?utm_source=android&utm_medium=share&utm_campaign=question

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