Question

compass starts from rest and attains a speed of 72km/hr in 60 seconds. calculate the acceleration of motion and also the distance covered by bus during this time
with proper explanation​

Answer 1

Hey mate thank for the question

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Answer 2

Answer:

Acceleration of the compass

➪ ⅓ m/s²

Distance travelled during acceleration

➪ 600 meter

Step by step explanations :

given that,

compass starts from rest and attains a speed of 72km/hr in 60 seconds.

here,

initial velocity of the compass = 0 m/s

[it was initially at rest]

final velocity of the compass = 72 km/h

= 72 × 1000 m/3600 s

= 20 m/s

time to accelerate = 60 seconds

let the acceleration produced by the compass be a

now we have,

initial velocity(u) = 0 m/s

final velocity(v) = 20 m/s

time taken(t) = 60 seconds

acceleration = a

by the equation of motion,

v = u + at

putting the values,

20 = 0 + a(60)

60a = 20

a = 20/60

a = ⅓ m/s²

acceleration of the compass

= ⅓ m/s²

now,

also from the equation of motion

v² = u² + 2as

again putting the values,

(20)² = (0)² + 2(⅓)s

2s/3 = 400

2s = 1200

s = 1200/2

s = 600 m

so,

distance travelled during acceleration

= 600 meter

____________________

Acceleration of the compass

➪ ⅓ m/s²

Distance travelled during acceleration

➪ 600 meter