complele the median from the
following data:
class mark (xi)
115 125 135 145 155 165 175
185 195
Frequency (fi)
6 25 48 72 116 60 38 22 13
Also find the mean and mode of the above data.
plz help mee.......
Answers
Here we are given the mid-values. So, should first find the upper and lower limits of the various classes. The difference between two consecutive values is h=125−115=10.
∴ Lower limit of a class = Mid-value- h/2, Upper limit = Mid-value + h/2.
Calculation of Median
Mid-value Class groups Frequency Cumulative Frequency
115 110-120 6 6
125 120-130 25 31
135 130-140 48 79
145 140-150 72 151
155 150-160 116 267
165 160-170 60 327
175 170-180 38 365
185 180-190 22 387
195 190-200 3 390
N=∑f
i
=390
We have,
N=390∴
2
N
=
2
390
=195
The cumulative frequency just greater than N/2 i.e.195 is 267 and the corresponding class is 150−160. So, 150−160 is the median class.
∴l=150,f=116,h=10,F=151
Now,
Median =l+
f
2
N
−F
×h
⇒Median=150+
116
195−151
×10=153.80
Answer:
its ok dude ...................
Anyway kaise ho