Question

Complement of function (A+B+C)' using theorem and laws is *

(A')+B+C

(A+B)'+C

A'B'C'

A+B+C

​

Answer 1

Answer:

C) A'B'C' is the compliment of the function.

Answer 2

The complement of (A+B+C)' using theorems and laws is simply (A+B+C)

Given:

The complement of the function (A+B+C)'

To find:

The simplified expression for the complement of (A+B+C)' using theorems and laws

Solution:

First, we can use De Morgan's Law to distribute the complement over the parentheses in (A+B+C)':

(A+B+C)' = A'B'C'

Next, we can use the double negation theorem to simplify the expression further:

A'B'C' = (A+B+C)'''

Using the double complement theorem, we can simplify this to:

(A+B+C)''' = (A+B+C)

Therefore, the complement of (A+B+C)' using theorems and laws is simply (A+B+C).

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