complementry angle of 36°36'
xenon1:
thanks
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Complementary angle is always equal to 90°
so let the required angle be x
x+36=90
x=54
thus the required angle is 54°
so let the required angle be x
x+36=90
x=54
thus the required angle is 54°
Answered by
0
1'has 1/60 degree,36' has 36/60 degree
then 36° 36' has 36+36/60 degree =2196/60 =36.6°
then its complementary angle is 90-36.6 = 53.4degree
then 36° 36' has 36+36/60 degree =2196/60 =36.6°
then its complementary angle is 90-36.6 = 53.4degree
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