complete it 2,4,6,8....,128
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Answered by
1
HEY MATE !!!
2,4,6,8,...., 128
form an AP , where
a= 2
d= 4-2= 2
An = 128
An= a+(n-1)d
128= 2+ (n-1)2
126= (n-1)2
n-1=63
n=64
thus there are total 64 terms in AP
So,in between 8 and 128, there are 59 terms:
10 12 14 16 ..... 124 126 128
HOPE YOU'VE FOUND IT IMFORMATIVE !!!
PLEASE MARK AS BRAINLIEST
THANKS!!
Answered by
0
2,4,6,8,10,12,14,16,18,20,22,24,26,
28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100,102,104,106,108,110,112,114,
116,118,120,122,124,126,128
total number = 64
hope it will help you.
mark it as brainliest
28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100,102,104,106,108,110,112,114,
116,118,120,122,124,126,128
total number = 64
hope it will help you.
mark it as brainliest
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