Question

Complete square −3n² + 4n − 59 = −4n²

Answer 1

Answer:

The required numeric value of n is - 2 ±√63.

Step-by-step explanation:

Given equation : - 3n^2 + 4n - 59 = - 4n^2

= > - 3n^2 + 4n - 59 = - 4n^2

Adding + 4n^2 on both sides of the polynomial :

= > - 3n^2 + 4n - 59 + 4n^2 = - 4n^2 + 4n^2

= > - 3n^2 + 4n^2 + 4n - 59 = 0

= > n^2 + 4n - 59 = 0

Adding 4 to both sides :

= > n^2 + 4n + 4 - 59 = 4

= > n^2 + 2( 2 n ) + ( 2 )^2 = 4 + 59

By using : a^2 + 2ab + b^2 , n^2 + 2( 2n ) + 2^2 = ( n + 2 )^2

= > ( n + 2 )^2 = 63

= > n + 2 = ±√63

= > n = - 2 ±√63

Hence the required numeric value of n is - 2 ±√63.