Question

complete the activity to sum of natural numbers between 1 and 140 which are divisble by 4?​

Answer 1

Answer:

4,8,12,....140 total 35 terms;

First number is 4,

common difference is 4,

last term is=140;

Sum of all the numbers= n/2(a+T)

=(35/2)(4+140)

=(35/2)*144

=2520

Step-by-step explanation:

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Answer 2

Answer:

Sum=2520

Step-by-step explanation:

common difference(d)=4

a1=4 an=140

an=a1+(n-1)d

140=4+(n-1)4

140-4=(n-1)4

136/4=n-1

34+1=n

35=n

$sum = \frac{n}{2} (2a1 + (n - 1)d)$

Sum=35/2(2*4+(35-1)4)

Sum=35/2(8+34*4)

Sum=35*144/2

Sum=2520