complete the addition and subtraction box (a) 2/3,4/3,1/3,2/3
Answers
Step-by-step explanation:
(a) \frac{2}{3}+\frac{4}{3}=\ \frac{2+4}{3}=\frac{6}{3}=2
3
2
+
3
4
=
3
2+4
=
3
6
=2
\frac{1}{3}+\frac{2}{3}=\frac{1+2}{3}=\frac{3}{3}=1
3
1
+
3
2
=
3
1+2
=
3
3
=1
Subtraction:
\frac{2}{3}-\frac{1}{3}=\frac{2-1}{3}=\frac{1}{3}
3
2
−
3
1
=
3
2−1
=
3
1
\frac{4}{3}-\frac{2}{3}=\frac{4-2}{3}
3
4
−
3
2
=
3
4−2
=\frac{2}{3}
3
2
\frac{1}{3}+\frac{2}{3}=\frac{1+2}{3}=\frac{3}{3}=1
3
1
+
3
2
=
3
1+2
=
3
3
=1
Answer:
We will use the concepts of fractions to solve this.
Let us proceed to find the missing numbers in the given box.
Let us use the Addition and Subtraction of numbers to solve the given problem.
(a)
2/3 + 4/3 = (2 + 4)/3 = 6/3 = 2
1/3 + 2/3 = (1 + 2)/3 = 3/3 = 1
2/3 - 1/3 = (2 - 1)/3 = 1/3
4/3 - 2/3 = (4 - 2)/3 = 2/3
1/3 + 2/3 = (1 + 2)/3 = 3/3 = 1