Question

Complete the analogy
Heat:joule::specific heat:​

Answer 1

Answer:

Heat : Joule :: Specific heat : Joule per Kelvin

Answer 2

The completed analogy is

Heat:joule::specific heat: $\frac{J}{Kg \ K}$

Explanation:

1. Here the analogy is based on the parameters and their units.
2. The unit of heat is the joule (J).
3. Specific heat is defined as the amount of heat required to raise the temperature of a  unit mass of a substance by 1 degree.
4. Therefore, its unit becomes: $\frac{J}{Kg \ K}$.