complete the congruence statement ∆pQS=
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In ΔBAT and ΔBAC,
given triangles are congruent
so the corresponding parts are:
B↔B,
A↔A,
T↔C.
Thus, ΔBCA≅ΔBTA [By SSS congruence rule]
In ΔQRS and ΔTPQ,
given triangles are congruent
so the corresponding parts are:
P↔R,
T↔Q,
Q↔S
Thus, ΔQRS≅ΔTPQ [By SSS congruence rule].
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