Question

.Complete the equation of conservation of momentum for two objects A and B moving with different velocities along straight line: ______+ mB uB = mA vA + ______________​

Answer 1

Answer:

HELP! its so hard!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

Answer:

maua + mbub = mava + mbvb

Explanation:

By 3rd law of motion  

FAB = -FBA (1)

By 2nd law of motion  

F = ma. (2)

By 1st equation of motion

a = v-u/t. (3)  

Using (2) and (3) in (1)

FAB = ma(va-ua/t). (4)

Similarly

FBA = mb(vb-ub/t). (5)

Using (4) and (5) in (1)

ma(va-ua/t) = -(mb(vb-ub/t))

t will get cancelled

(mv)a - (mu)a = -(mv)b + (mu)b

maua + mbub = mava + mbvb