complete the following:-a)CH3-CH=CH2+HBr in the presence of peroxide gives?
b)CH3CH-Br-CH2-CH3+KOH(alc) gives?
Answers
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Answer: The products of the following reactions are given below.
Explanation:
1. When 1-propene reacts with hydrogen bromide in the presence of peroxide, the more electronegative atom which is bromine gets attached to the carbon atom which has more number of hydrogen atoms. This reaction is named as Anti-Markovnikov's reaction.
2. When 2-bromo-butane is reacted with alcoholic KOH, it will produce 2-butene because the alkene produced is the distributed alkene.
As, the reactant has 2 beta-hydrogen atoms, the terminal hydrogen atom is not lost in the reaction because it would have produced 1-butene, which is not the distributed alkene. Hence, the major product is 2-butene. This reaction is known as dehydrohalogentaion reaction.
The reactions for this are provided in the image below.
