Question

Complete the following acid-base reactions and name the products: (i) CH3CH2CH2NH2 + HCl (ii) (C2H5)3N + HCl

Answer 1

Dear Student,

(i) N-propylamine reacts with HCl to produce N-propyl ammonium chloride.

CH3-CH2-CH2-NH2 + HCl → CH3-CH2-CH2-N+H3Cl-

Product formed => N-propyl ammonium chloride

(ii) Triethyl amine reacts with HCl to produce Tri-ethyl ammonium chloride

(CH3-CH2)3N + HCl → (CH3-CH2)3N+HCl-

Product formed => Tri-ethyl ammonium chloride

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