Complete the following activity.
(1) In ∆RST, angleS = 90°, angle T = 45°, RT = 12 cm. Find RS and ST.
In ∆ RST, angleT = 45°, angleS = 90°,
angleR=
According to 45°- 45°-90° theorem
RS =
1/√2 x
=
st = ×rt
=
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Answer:
△RST
∠S=90
∘
∠T=45
∘
RT=12cm
∠R=180
∘
−∠S−∠T [∵ Sum of all 3 sides of a triangle in supplementary]
=180
∘
−90
∘
−45
∘
∠R=45
∘
sinT=
RT
RS
⇒sin45
∘
=
12
RS
⇒
2
1
=
12
RS
⇒RS=6
2
∵∠R=∠T
⇒ST=RS [Sides opposite in equal angle are equal]
⇒ST=6
2
[From above 2 equations]
Hence RS=6
2
ST=6
2
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