Math, asked by uuzer7231, 3 months ago

Complete the following activity.​

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Answers

Answered by bagkakali
1

here a=₹ 1,80,000

d= ₹ 10,000

tn= ₹ 2,50,000

n= ?

tn=a+(n-1).d

2,50,000=1,80,000+(n-1).10,000

(n-1)×10,000=2,50,000-1,80,000

=> (n-1)×10,000=70,000

=> n-1=70,000/10,000

=> n-1=7

=> n=7+1

=> n=8

Answered by daspragati
1

Answer:

n = 8 years and (n - 1) = 7 years

Step-by-step explanation:

Salary at the beginning = Rs. 180,000/year

Increment = Rs. 10,000

Salary at the end of n no. of years = Rs. 250,000/year

d = Rs. 10000, t_{n} = Rs. 250,000, a = Rs. 180,000

t_{n} = a + (n - 1)d

=> 250,000 = 180,000 + {(n - 1) X 10000}

=> 250,000 - 180,000 =  (n - 1) x 10000

=> 70000/10000 = (n - 1)

=> n - 1 = 7

=> n = 8 years.

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