Question

Complete the following activity.​

Answer 1

Given→

$sin²θ + cos²θ = ☐$

$\frac{sin²θ}{sin²θ} + \frac{cos²θ}{sin²θ} = \frac{ ☐}{sin²θ} \\ \\ 1 + ☐ = ☐$

To find→

Value that can be substituted in ☐

Solution→

[tex]sin²θ + cos²θ =1[/tex]

$\frac{sin²θ}{sin²θ} + \frac{cos²θ}{sin²θ} = \frac{ 1}{sin²θ} \\ \\ 1 + {cot}^{2}θ = {cosec}^{2}$