Math, asked by ashkansohelsha, 2 months ago

complete the following activity to determine the nature of the root of the quadratic equation 2x2 - 5x+3=0.​

Answers

Answered by amansharma264
152

EXPLANATION.

Nature of the quadratic equation.

⇒ 2x² - 5x + 3 = 0.

As we know that,

⇒ D = Discriminant Or b² - 4ac.

Put the value in the equation, we get.

⇒ D = (-5)² - 4(2)(3).

⇒ D = 25 - 24.

⇒ D = 1.

Nature of roots are real and equal : D = 0.

                                                                                                                           

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) = Real and different, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal Or complex conjugate.

Answered by Anonymous
168

{\large{\pmb{\sf{\underline{Given \; that...}}}}}

{\green{\bigstar}} A quadratic equation is given as {\red{\sf{2x^{2} - 5x + 3 = 0}}}

{\large{\pmb{\sf{\underline{To \; find...}}}}}

{\green{\bigstar}} Determine the nature of the root of the given quadratic equation.

{\large{\pmb{\sf{\underline{Solution...}}}}}

{\green{\bigstar}} The nature of the root of the quadratic equation {\red{\sf{2x^{2} - 5x + 3 = 0}}} is {\red{\sf{Real}}} and {\red{\sf{Equal}}}

{\large{\pmb{\sf{\underline{Knowledge...}}}}}

Some knowledge about Quadratic Equations -

★ Sum of zeros of any quadratic equation is given by ➝ α+β = -b/a

★ Product of zeros of any quadratic equation is given by ➝ αβ = c/a

★ Discriminant is given by b²-4ac

  • Discriminant tell us about there are solution of a quadratic equation as no solution, one solution and two solutions.

★ A quadratic equation have 2 roots

★ ax² + bx + c = 0 is the general form of quadratic equation

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━

{\large{\pmb{\sf{\underline{Using \; concepts...}}}}}

{\red{\bigstar}} Discriminant is given by the given:

{\small{\underline{\boxed{\sf{b^{2} - 4ac}}}}}

{\large{\pmb{\sf{\underline{Full \; Solution...}}}}}

{\small{\underline{\boxed{\sf{b^{2} - 4ac}}}}}

{\sf{:\implies b^{2} - 4ac}}

{\sf{:\implies Given \: that \: = 2x^{2} - 5x + 3 = 0}}

{\sf{:\implies (-5)^{2} - 4(2)(3)}}

{\sf{:\implies -5 \times -5 - 4(2)(3)}}

{\sf{:\implies 5 \times 5 - 4(2)(3)}}

{\sf{:\implies 25 - 4(2)(3)}}

{\sf{:\implies 25 - 4(6)}}

{\sf{:\implies 25 - 4 \times 6}}

{\sf{:\implies 25 - 24}}

{\sf{:\implies 1}}

Henceforth, the discriminant is 1. Therefore, the nature of the root of the given quadratic equation is Equal and Real.

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