Question

Complete the following activity to find the 3th term of an A.P. 3, 8, 13, 18,...
Here, a-3, d=
t30 = ?
tn=a+ (Formula)
t30=3+ (Substituting the values)
t30=​

Answer 1

Answer:

d=5 , tn=n-2, t30=3+(30-1) d

Step-by-step explanation:

d=t2-t1=5

t30=a+29d\[a+(n-1) d] where n=30

tn =a+(n-1) d

so t30=3+29(5)=3+245=248