Question

() Complete the following activity to find the fourth term from the end of the A.P. – 11, -8, –5, ..., 49. - -
Reversing the terms of the given A.P., we get, 49, ..., -5, -8, - 11.
This is an A.P. We have to find the fourth term i.e. t4 ?
d = = ? Here, a=t, 1 (Formula) 1 = - n :: te= 49+(4 – 1) (-3) Simplifying, ta= to use spectacles. Complete the follow​

Answer 1

Answer:

a = -11

d = -8 - (-11) = -8 + 11

d = 3

an = 49

an = a+(n-1)d

49 = -11+(n-1)3

49+11 = (n-1)3

60 ÷ 3 = n-1

20 = n-1

20 + 1 = n

n = 21