Question

Complete the following activity to find the sum of first 50 terms of the A.P.
8, 12, 16, ....​

Answer 1

Answer:

a=8

d=a1-a2

=12-8

=4

n=50

Sn =n/2[2a+(n-1)d]

=50/2[2(8)+(50-2)4]

=25[16+(49)4]

=25[16+196]

Sn=5300

PLEASE MARK IT BRAINLIEST

Answer 2

Answer:

5300

Step-by-step explanation:

Sn=n/2[2a+(n-1) d]

=50/2[2×8+(50-1)4]

=25[16+196]

=25[212]= 5300

Please mark as brainliest