Question

complete the following activity to find three - digit natural numbers divisible by 5 three - digit natural numbers divisible by 5 are 100,105,110,....,995
here ,a = 100,d=105-100=5​

Answer 1

Answer:

The three digit natural numbers divisible by 5 are 100, 105, 110, …,995 The above sequence is an A.P. ∴ a = 100, d = 105 – 100 = 5 Let the number of terms in the A.P. be n. Then, tn = 995 Since, tn = a + (n – 1)d ∴ 995 = 100 +(n – 1)5 ∴ 995 – 100 = (n – 1)5 ∴ 895 = (n – 1)5 ∴ n – 1 = 895/5 ∴ n – 1 = 179 ∴ n = 179 + 1 = 180 ∴ There are 180 three digit natural numbers which are divisible by 5.Read more on Sarthaks.com - https://www.sarthaks.com/845045/find-how-many-three-digit-natural-numbers-are-divisible-by-5?show=845055#a845055

Step-by-step explanation:

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Answer 2

Answer:

Here Natural no. means 1 to infinity

so, We need a three digit natural no. which is divisible by 5.

so the smallest three didgit natural no. which is devided by 5 is 100.