Math, asked by Anonymous, 9 months ago

Complete the following activity to solve the simultaneous equations.
5x + 3y = 9 -----(I)
2x - 3y = 12 ----- (II)​

Answers

Answered by BlackWizard
5

Answer:

5x + 3y = 9 -----(I)

2x − 3y = 12 ----- (II)

Add (I) and (II)

7x = 21

x = 3

Putting the value of x = 3 in (I) we get

5(3)+3y=9

⇒15+3y=9

⇒3y=9−15=−6

⇒y=−2

Thus, (x, y) = (3, −6).

Answered by aaditya1234567890
5

Answer:

x = 3

y = -2

Step-by-step explanation:

5x + 3y = 9 -----(I)

2x - 3y = 12 ----- (II)​

Adding (I) and (II)

   5x + 3y = 9

+  2x - 3y = 12

------------------------

   7x        = 21

x = 3

Substituting x = 3 in (I)

5(3) + 3y = 9

15 + 3y  = 9

3y = 9 - 15

3y = -6

y = -2

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