Complete the following chemical equations and balance them. 1. AgCl(s) light > Ag(s) + 2. Cl2(g) + KBr(aq) → + Br (g) 3. BaCl, + → BaSO4 + Naci 4. CuO + → CuSO4 + H2O 5. Pb(NO3)2 + NO, + O2
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Explanation:
We need to find value of (9
4/3
÷27
2/3
)×3
3/2
9
4/3
=3
8/3
and 27
2/3
=3
6/3
So,
3
6/3
3
8/3
= 3
8/3−6/3
= 3
2/3
,
⇒3
2/3
.3
3/2
= 3
(2/3+3/2)
= 3
13/6
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