Question

Complete the following chemical reaction
Na2Cr207 + KCI →​

Answer 1

Answer:

Na2Cr2O7 + 2KCl ---------> K2 Cr2O7 + 2

Answer 2

Answer:

here acidic medium / basic medium must be mentioned

Explanation:

na2cr2o7+kcl = cr+3 + cl2

if acidic medium

suppose h2so4

then the reaction will be

na2cr2o7+kcl + h2so4 = na2so4+k2so4+cr+3 +cl2

here the only possibility is acidic medium because k2cr2o7 acts as oxidizing acid only when acidic medium is mentioned

if you want balance  reaction you can balance out

by adding valency factor method

first find valency factors of na2cr2o7 and kcl

valency factor = index of atom * change in oxidation state

=2(3)

=6

valency factor of na2cr2o7 = 6

valency factor  of kcl = 1

now multiply the valency factor of one with other

it becomes like this

na2cr2o7+6kcl +h2so4 = na2so4+k2so4+cr+3 +cl2

now apply ooc method

o means other than oxygen atom

so balance other than oxygen

na2cr2o7+6kcl+h2so4=na2so4+3k2so4+2cr+3 + 3cl2

now balance oxygen as other atoms are balanced

na2cr2o7+6kcl+5h2so4=na2so4+3k2so4+2cr+3 +3cl2

now balance oxygen

na2cr2o7+6kcl+5h2so4=na2so4+3k2so4+2cr+3 +3cl2 + 11h2o

now balance hydrogen

na2cr2o7+6kcl+5h2so4 +12h+ = na2so4+3k2so4+2cr+3+3cl2+11h2o

balance charge by adding e

na2cr2o7+6kcl+5h2so4+12h+ +9e=na2so4+3k2so4+2cr+3+3cl2+11h2o