Question

Complete the following crosses to show F1 generation and self crossed F2 generation using a Punnet square and state the phenotypic ratio for both: a. TT x tt b. RRYY x rryy​

Answer 1

Answer:

A monohybrid cross results in a phenotypic ratio of 3:1 (dominant to recessive), and a genotypic ratio of 1:2:1 (homozygous dominant to heterozygous to homozygous recessive).

Explanation:

Cross is made between a homozygous dominant plant with yellow round seeds to another homozygous recessive green wrinkled seeds, is called Dihybrid cross. In the F2 generation, phenotypically, 9 are round, yellow, 3 round green 3 wrinkled yellow 1 wrinkled green and genotypically 1:2:2:4:1:2:1:2:1

So, the correct option is ‘1:2:2:4:1:2:1:2:1’.