Question

Complete the following equations:
(i) Cl₂ + NaOH(cold and dilute) →
(ii) Fe³⁺ + SO₂ + H₂O →

Answer 1

(i) reaction of dichlorine with cold and dilute solution of sodium hydroxide is given as
$2NaOH+Cl_2\rightarrow NaCl+NaClO+H_2O$

NaClO , sometimes it is written as NaOCl . it is known as sodium chlorate .

hence, when two mole of cold and dilute solution of sodium hydroxide reacts with one mole of dichlorine , one mole of sodium chloride , one mole of sodium chlorate and one of water form in place of products.

(ii) you should know SO2 acts as reducing agents. it reduces Fe³+ to Fe²+ and itself get oxidised SO4²-

reaction is :
step 1 :- $Fe^{3+}+e^-\rightarrow Fe^{2+}$

step 2 :- $SO_2+2H_2O\rightarrow SO_4^{2-}+4H^++2e^-$
multiplying 2 with step 1 and adding step 2 , we get,

$2Fe^{3+}+SO_2+2H_2O\rightarrow 2Fe^{2+}+SO_4^{2-}+4H^{+}+e^{-}$