Complete the following proof.
Prove: The diagonals of a rectangle are equal.
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ABCD is a rectangle with AC and BD as its diagonals .
ABCD is a rectangle
so, angle A = 90° , AB=BC
AB||BC and AB is transversal
so, angle A + angle B = 180°
= angle B =90°
In ∆ABD and ∆BAC
AB=BA
angle A = angle B
AD=BC
so, ∆ABD ≈ ∆BAC (by SAS)
BD=AC (by C.P.C.T)
Hence, the diagonals of a rectangle are equal.
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