Question

Complete the following reaction:
Xe + PtF6 →

Answer 1

Answer:

Xe + PtF6 ----278K----> [Xe]+[PtF6]-

Answer 2

The complete reaction is as follows-

$Xe+PtF_6\rightarrow Xe^+[PtF_6]^-$.

• Xe or Xenon is an inert gas. It resides in group 18 of the modern periodic table.
• Xe reacts with platinum hexafluoride to form a complex $Xe[PtF_6]$. This complex again exists as a Xe ion and The complete reaction is as follows-
• $[PtF_6]^-$ anion.
• Hence the reaction is as follows-

$Xe+PtF_6\rightarrow Xe^+[PtF_6]^-$.