Complete the following reactions:Cr2O7 2- + Sn2+ + H+ ---MnO4 - + I- + OH- ---
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Answer:
) Cr2O72– + 3Sn2++ 14H+ → 2Cr3+ + 3Sn4+ + 7H2O
(ii) MnO4– + 5Fe2– + 8H+ → 5Fe3+ + Mn2+ + 4H2O
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Cr₂O₇⁻² + 3Sn₂⁺ + 14H⁺ --> 2Cr⁺³ + 3Sn⁺⁴ + 7H₂O
MnO₄⁻² + 5Fe⁺² + 8H⁺--> 5Fe⁺³+ Mn₂ + 4H₂O
- The above-given redox reactions can be balanced by adding H₂O molecules on the right-hand side in the acidic medium.
- The hydrogen atoms can be balanced by adding an H⁺ ion on the left-hand side in the acidic medium.
- Then balance the hydrogen atoms.
Hence, the complete reactions are
Cr₂O₇⁻² + 3Sn₂⁺ + 14H⁺ --> 2Cr⁺³ + 3Sn⁺⁴ + 7H₂O
MnO₄⁻² + 5Fe⁺² + 8H⁺--> 5Fe⁺³+ Mn₂ + 4H₂O
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