Question

Complete the given number /
letter / figure analogy by choosing the correct
answer from the given alternatives.

1, 496 : 204 : : 329 : ?
1) 90 |
2) 110
3) 115
4) 135 -
7 336 , 720
17: 110" ? : 156
A
?
3, 11 18 32 60 : 17 30 56 108 :: 13 24 46 90 :
1) 17 36 68 138
2) 19 30 52 124
3) 19 36 70 136
4) 19 36 70 138
4. FLOWERY : 21 O 12 D 22 I 2 :: BUNCHES :
1) 25 F 13 X 19 V 8
2) 2 F 14 X 8 V 19
3) 25 H 13 P 19 R 8
4) 2 H 14 P 8 8 19
5. AWSXC: RNJOT :: ? : UQMRW
1) FAVZD
2) DZVAF
3) IN R M H.
4) DINJF​

Answer 1

Answer:

hey mate here is your answer

Step-by-step explanation:

please post full question hope you will understand please mark my answer as a brainliast

Answer 2

Answer:

1) The correct answer is option 3

2) $\frac{7}{11}: \frac{336}{110}:: ?: \frac{720}{156}$

(1) $\frac{9}{17}$

(2) $\frac{9}{13}$

(3) $\frac{11}{13}$

(4) $\frac{11}{17}$

The correct answer is option 2

3) $11,18,32,60: 17,30,56,108:: 13,24,46,90: ?$

(1) 17,36,68,138

(2) 19,30,52,124

(3) 19,36,70,136

(4) 19,36,70,138

The correct answer is option 4

4) FLOWERY:21 O 12 D 2212 :: BUNCHES:

(1) $25 \mathrm{~F} 13 \times 19 \mathrm{~V} 8$

(2) $2 F 14 \times 8 V 19$

(3) 25 H 13 P 19 R 8

(4) 2 H 14 P 8 R 19

The correct answer is option 1

5. A W S X C: R N J O T : :? : U Q M R W

(1)$F A V Z D$

(2) D Z V A F

(3) I N R M H

(4) D I N J F

The correct answer is option 2

Step-by-step explanation:

1) Given :- 496 : 204 :: 329 : ?

Solution:-

In analogy, we have to apply the same logic in the next ratio .

$== > 496 = 512 - 16 \\== > 8^3 - 2 * 8$

$== > 204 = 216 - 12\\ == > 6^3 - 2 * 6\\Difference= 8 - 6 = 2$

Therefore,

$== > 329 = 343 - 14\\ = 7^3 - 2 * 7$

The next term will be:-

$7 - 2 = 5$

$== > 5^3 - 2 * 5 \\= 125 - 10 \\= 115 (Ans.)$

2) Given:  $\frac{7}{11}: \frac{336}{110}:: ?: \frac{720}{156}$

Solution:

$\frac{7^{3}-7}{11^{2}-11}=\frac{336}{110}$

$\frac{9^{3}-9}{13^{2}-13}=\frac{720}{156}$

3) Given: $11,18,32,60: 17,30,56, 108:: 13,24,46,90: ?$

Solution:

$\begin{aligned}&13+6=19 \\&24+12=36 \\&46+24=70 \\&90+48=138\end{aligned}$

4) Given:

FLOWERY:21 O 12 D 2212 :: BUNCHES:

(1) $25 \mathrm{~F} 13 \times 19 \mathrm{~V} 8$

(2) $2 F 14 \times 8 V 19$

(3) 25 H 13 P 19 R 8

(4) 2 H 14 P 8 R 19

Solution:

Sol. F L OWE R Y: 21 O 12 D 22 72

$\\ \begin{array}{llllllll}21 & 15 & 12& 42& 29 &2 & 21 & 15 & 12&42&29&2\end{array}$

(Back Position)

B U N C H E S:25 F 13 X 19 V8

$\left(\begin{array}{lllllll}25 & 6 & 13 & 24 & 19 & 22 & 8\end{array}\right)$

5) Given:

A W S X C: R N J O T : :? : U Q M R W

(1) $F A V Z D$

(2) D Z V A F

(3) I N R M H

(4) D I N J F

Solution:

The solution is shown in the figure puzzle2.png