Question

Complete the missing parts of the missing process in estimating/approximating square roots up to the nearest hundredths.​

Answer 1

The nearest hundredths place  of $\sqrt{12}$   is 3.46

Explanation:

Step 1 of 5: The $\sqrt{12}$  lies between $\sqrt{9}$ and $\sqrt{16}$

Step 2 of 5: Can be written as $\sqrt{9}$  < $\sqrt{12}$ < $\sqrt{16}$

                                                 = 3 < $\sqrt{12}$ < 4

Step 3 of 5: First estimation (Nearest Tenths)

                      (a)3.4                  (b)3.5

                       $\sqrt{12}$ is in between 3.4 and 3.5 but closer to 3.4

Step 4 of 5: Further estimation (Nearest Hundredths)

                      (a)3.46                   (b)3.47

                       Since  $\sqrt{12}$ is closer to $\sqrt{16}$ than $\sqrt{9}$

                        then  $\sqrt{12}$ ≅3.46

Step 5 of 5: therefore the approximated value of   $\sqrt{12}$ into nearest     hundredths is 3.46