Complete the reaction: c6h5n2cl 1) hbf4 2) nano2/o3, ∆
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● Answer with explanation -
# Step I -
When benzene diazonium chloride is treated with HBF4, fluorobenzene is formed.
C6H5-N2Cl + HBF4 → C6H5-F + N2 + HCl + BF3
# Step II -
Fluorobenzene on reaction with NaNO2/O3 gives nitrobenzene.
C6H5-F + NaNO2 + ∆ → C6H5-NO2 + NaF
# Overall reaction -
Overall reaction can be written as -
C6H5-N2Cl (HBF4 + NaNO2/O3) → C6H5-NO2
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