Question

complete the reaction (CH3)3CCH2Br in the presence of koh
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Answer 1

Answer:

This process is used to form alkyl iodide as a product.

Alcohol KOH is dehydrohalogenating agent and peroxide is used to form anti-markovnikov product.

CH

3

−CHBr−CH

3

alc.KOH

CH

3

−CH=CH

2

HBr

peroxide

CH

3

CH

2

CH

2

Br

Nal

acetone

CH

3

CH

2

CH

2

I

Answer 2

Answer:

CH

3

−CH(Br)−CH

3

alc.KOH

A

HBr

peroxide

B

NaI

acetone

C