Complete the reaction H3BO3+OH- .Please reply asap. I will mark youranswer as brainiest.
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Concerning your question about the reaction of boric acid with sodium hydroxide. Boric acid reacts with sodium hydroxide to produce sodium tetraborate and water according to the following equation:
4 H3BO3 + 2 NaOH → Na2B4O7 + 7 H2O
Boric acid H3BO3 is weak acid and its reaction with sodium hydroxide can be carried out by the addition of excess of mannitol. Mannityl boric acid complex formed is strong acid and the equation as follows:
4 H3BO3 + 2 NaOH mannitol → Na2B4O7 + 7 H2O
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