Question

complete the series 4, 12, 84, 3612, ? ​

Answer 1

Answer:

In the given series i observed the following pattern

Terms can be written as

4×3(2^2-1)=12, 12×7(3^2-2)=84, 84×43(7^2-6)=3612

Here,term being squared is from the product of last pair, and a number one less to that term is subtracted from it.

As, in first term we have 4×3=12

So for next,squaring of 3,subtracted by a number one less i.e. 2= 3^2-2=9-2=7

So 12×7=84,similarly for next term to obtain squaring of 7 and subtracted by 6, we get 43

84×43=3612

So next would be 3612×(43^2-42)=3612×1807=65,26,884

hope this helps