complete the serirs 36,39,30,28,29,_,_
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36+3=39…..(1)
39–9=30…..(2)
30–2=28……(3)
28+1=29…….(4)
From eq.1 & eq.2 we know that after addition we have to subatract value of unit place from number.
29–9=20
From eq.1 & eq.3 we get that we have to substract a number which is 1 less than the number added earlier.
For eq.3 we substract 2 that is 1 less than 3 that added to eq.1
Accordingly,
20-0=20
36,39,30,28,29,20,20
36+3=39…..(1)
39–9=30…..(2)
30–2=28……(3)
28+1=29…….(4)
From eq.1 & eq.2 we know that after addition we have to subatract value of unit place from number.
29–9=20
From eq.1 & eq.3 we get that we have to substract a number which is 1 less than the number added earlier.
For eq.3 we substract 2 that is 1 less than 3 that added to eq.1
Accordingly,
20-0=20
36,39,30,28,29,20,20
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