Complete the square to rewrite y = x2 – 6x + 15 in vertex form. Then state whether the vertex is a maximum or minimum and give its coordinates. A. Maximum at (–3, 6) B. Minimum at (–3, 6) C. Maximum at (3, 6) D. Minimum at (3, 6)
Answers
Answer:
Option C is correct. Maximum at (3,6)
Step-by-step explanation:
We are given a equation of parabola in standard form,
we need to convert into vertex form,
Using completing square method,
( Add and subtract square of half of coefficient of x)
This would be vertex form of parabola,
Vertex: (3,6)
The leading coefficient of parabola is positive.
Therefore, At vertex we will get maximum.
Maximum at (3,6)
Thus, Option C is correct. Maximum at (3,6)
Answer:
C. Maximum at (3, 6)
Step-by-step explanation:
Here, the given equation is,
-------(1)
Which is the equation of parabola,
Since, the vertex form of parabola is,
Where, (h,k) is the vertex of the parabola,
If a > 0 then the value of y is minimum at (h,k),
While, if a < 0, then the value of y is maximum at (h,k),
Now, from equation (1),
By comparing this equation with the vertex form of the parabola,
We get, (h,k) = (3,6)
And, a = 1 > 0
Hence, y is minimum at (3,6).