Complete the table
width
Length
Perimeter
Area
14 cm
sem.
Answers
Step-by-step explanation:
Formulas for Area and Perimeter of the Rectangle are given below :
• Perimeter of the rectangle = 2(l + w) units
• Length of Rectangle = p/2 - w units
• Width(w) of Rectangle = p/2 - l units
• Diagonal of Rectangle = √(l 2 + w 2 ) units
• Area of Rectangle = l x w sq.units
• Length of Rectangle = A/w units
• Width of Rectangle = A/l units
Some solved examples on Area and Perimeter of the Rectangle
1) Find the perimeter of a rectangle whose length and width are 25 m and 15 m respectively.
Solution :
Length = l = 25 m and Width = w = 15 m
∴ P = 2 ( l + w )
⇒ = 2 ( 25 + 15 )
⇒ = 2 x 40
⇒ = 80 m
Perimeter = 80 m
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2)How many rectangles can be drawn with 36 cm as the perimeter, given that the sides are positive integers in cm ?
Solution :
Perimeter = 36
⇒ 2 ( l + w ) = 36
⇒ l + w = 18
Since length and width are positive integers in centimeters. Therefore, possible dimensions are :
( 1, 17 )cm , ( 2, 16 ) cm , ( 3, 15 ) cm, (4 , 14) cm, ( 5,13) cm, ( 6, 12) cm , ( 7, 11) cm, ( 8, 10 ) cm, ( 9, 9) cm.
Hence, there are 9 rectangles.
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4) The length of a rectangular field is twice its width. A man jogged around it 5 times and covered a distance of 3 km. What is the length of the field?
Solution :
In completing one round of the field distance covered is equal to the perimeter of the field.
∴ Distance covered in 5 rounds = 5 x Perimeter
= 5 x 2 ( l + w