Complete the two-colomn proof.
Given: ∆JUG is an equilateral and Un is one of its medians
∆
Prove: ∆JUN ≈ ∆GUN
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Given :- Given: ∆JUG is an equilateral and UN is one of its medians .
Prove :- ∆JUN ≅ ∆GUN .
Solution :-
In ∆JUN and ∆GUN we have,
→ JN = GN { given that, UN is median of an equaliteral ∆JUG, so it will bisect the base. }
→ ∠JNU = ∠GNU { Median of an equaliteral ∆ is also perpendicular bisector of the opposite side. so both angle will be 90° }
→ UN = UN (common.)
then,
→ ∆JUN ≅ ∆GUN { By SAS congruence rule.}
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