complete these chemical reaction equations ii) - (aq) + H20 (1) + 03 (g) –
→
3) XeF2 + H2O
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The hydrolysis of xenon hexa fluoride gives
XeOF
4
. Further hydrolysis results in end product
XeO
3
XeF
6
+H
2
O→XeOF
4
+2HF.
XeOF
4
+H
2
O→XeO
2
F
2
+2HF
XeO
2
F
2
+H
2
O→XeO
3
+2HF
3XeF
6
+6H
2
O→2XeO
3
+Xe+12HF.
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