completing square method x^2+8x-48=0
saketshokeen20:
x^2+12x-4x-48=0. x^2-4x+12x-48. x(x-4)+12(x-4).(x+12)(x-4)
x=+4 or x=-12
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Answered by
1
x^2+12x-4x-48=0
x(x+12)-4 (x+12)=0
(x+12)(x+4)=0
(x+12) = 0 or (x+4) = 0
x= -4 or x = -12
hope this helps....
x(x+12)-4 (x+12)=0
(x+12)(x+4)=0
(x+12) = 0 or (x+4) = 0
x= -4 or x = -12
hope this helps....
thanks
ur welcome
its ok dear
Answered by
3
x^2+8x-48 = 0
x^2+12x-4x-48=0
x(x+12)-4(x+12)=0
(x+12)(x-4)=0
Hence,x=+4 or x=-12
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I hope it will help you
Thanks
x^2+12x-4x-48=0
x(x+12)-4(x+12)=0
(x+12)(x-4)=0
Hence,x=+4 or x=-12
.
.
.
.
I hope it will help you
Thanks
maharashtra
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