completing the sqare method
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Say we have a simple expression like x2 + bx. Having xtwice in the same expression can make life hard. What can we do?
Well, with a little inspiration from Geometry we can convert it, like this:

As you can see x2 + bx can be rearranged nearly into a square ...
... and we can complete the square with (b/2)2
In Algebra it looks like this:
x2 + bx+ (b/2)2=(x+b/2)2 "Complete the Square"
So, by adding (b/2)2 we can complete the square.
And (x+b/2)2 has x only once, which is easier to use.
Keeping the Balance
Now ... we can't just add (b/2)2 without also subtracting it too! Otherwise the whole value changes.
So let's see how to do it properly with an example:
Start with:  ("b" is 6 in this case) Complete the Square:

Also subtract the new term
Simplify it and we are done.

The result:
x2 + 6x + 7 = (x+3)2 − 2
And now x only appears once, and our job is done!
A Shortcut Approach
Here is a quick way to get an answer. You may like this method.
First think about the result we want: (x+d)2 + e
After expanding (x+d)2 we get: x2 + 2dx + d2 + e
Now see if we can turn our example into that form to discover d and e
Well, with a little inspiration from Geometry we can convert it, like this:

As you can see x2 + bx can be rearranged nearly into a square ...
... and we can complete the square with (b/2)2
In Algebra it looks like this:
x2 + bx+ (b/2)2=(x+b/2)2 "Complete the Square"
So, by adding (b/2)2 we can complete the square.
And (x+b/2)2 has x only once, which is easier to use.
Keeping the Balance
Now ... we can't just add (b/2)2 without also subtracting it too! Otherwise the whole value changes.
So let's see how to do it properly with an example:
Start with:  ("b" is 6 in this case) Complete the Square:

Also subtract the new term
Simplify it and we are done.

The result:
x2 + 6x + 7 = (x+3)2 − 2
And now x only appears once, and our job is done!
A Shortcut Approach
Here is a quick way to get an answer. You may like this method.
First think about the result we want: (x+d)2 + e
After expanding (x+d)2 we get: x2 + 2dx + d2 + e
Now see if we can turn our example into that form to discover d and e
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