Question

completing the square method x^2+6x+8=0​

Answer 1

Step-by-step explanation:

${x}^{2} + 6x + 8 = 0 \\ {x}^{2} + 4x + 2x + 8 = 0 \\ x(x + 4) + 2(x + 4) = 0 \\ (x + 4) (x + 2) = 0$

$x + 4 = 0 \\ x = - 4$

&

$x + 2 = 0 \\ x = - 2$