completing the square x^2-10x+9
fst..... solve
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Completing square method,
x²-10x+9
x²-10x = -9
(x)²-2(x)(5) = -9
Adding 5² on both sides,
(x)²-2(x)(5)+(5)² = -9+(5)²
(x-5)² = -9+25
(x-5)² = 16
x-5 = √16
x-5 = ±4
(i) x-5 = 4
x = 4+5
x = 9
(ii) x-5 = -4
x = -4+5
x = 1
Therefore,the zeroes of the polynomial are 1 and 9.
x²-10x+9
x²-10x = -9
(x)²-2(x)(5) = -9
Adding 5² on both sides,
(x)²-2(x)(5)+(5)² = -9+(5)²
(x-5)² = -9+25
(x-5)² = 16
x-5 = √16
x-5 = ±4
(i) x-5 = 4
x = 4+5
x = 9
(ii) x-5 = -4
x = -4+5
x = 1
Therefore,the zeroes of the polynomial are 1 and 9.
chandrashekhar4:
excellent
could you delete my answer please??
x^2 -5x+5. solve this alsooooo
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